I will write again what how to use value of boolean. And Tihs time, Write about Application of If statement.
It will guradually become more. enjoy create logic.
ロードマップ
Booleanの扱い方
If文の使い方
If文の使い方〜応用編〜 今回
ループ処理〜For文〜
ループ処理〜For文の応用〜
ループ処理〜While文〜
ループ処理〜While文の応用〜
ループ処理〜Do While文〜
ループ処理〜Do While文の応用〜
演算子の整理
演算子の応用
まとめ
Road Map
How to use Boolean
How to use if statement
Training of if statement This time
How to use loop statement 〜While〜
Training of Loop〜While〜
How to use loop statement 〜While〜
Training of Loop〜While〜
How to use loop statement 〜Do While〜
Training of Loop〜Do While〜
Summary of operator
Training of operator
Summary
If文の使い方〜応用〜
前回は、単純なIf文、条件が１つでTrue / Flaseの判定を行いました。
今回は「If文の応用」と称してBooleanの扱い方の応用編をやろうと思います。
Application of If statement
we tried basic If statement. next it Called Application of If statement. that is application of how to use boolean
This time, we will try to make the simple program. and I will show sample program. That is using technique of I wrote in blog.
・using program argument. and if argument is string charactor then print argument to console. if argument is number charactor then print result of calculate in 「+」「-」「*」「/」.
public static void main(String[] args) {
// Check program argument
if (args.length == 2) {
// Case2
int left = Integer.parseInt(args[0]);
int right = Integer.parseInt(args[1]);
System.out.println(left + " + " + right + " = " + left + right);
System.out.println(left + " - " + right + " = " + left - right);
System.out.println(left + " * " + right + " = " + left * right);
System.out.println(left + " / " + right + " = " + left / right);
} else {
System.out.println("Please set 2 arguments");
}
}
<Question1>
Make a program to print that if it's odd number print "it's odd number" and if it's even number print "it's even number".
<Querstion2>
Make a program to calculate area of triangle using 2 program arguments.
<Question3>
Like question2 make a program to calculate area of rectangle.
<Question4>
make a program to print like a sample , using program argument and print splited string.-----------------------------------
1: first harf:XXXXX
2: second harf:XXXXX
if (<result of logical operation1>) {
// processing1
} else if (<result of logical operation２>) {
// processing２
} else {
// processing3
}
perform conditional branching as above. the value of < ... > is "True" or "False".
Is shown blow.
int num = 1;
if (num == 1) {
System.out.println("num is " + num);
} else if (num == 2) {
System.out.println("num is" + num);
} else {
System.out.println("num is not 1 and ２");
}
Valiable "num" is in１ and result of processing display "num is 1". next i try change this code like this.
public static void main(String[] args) {
int num = Integer.parseInt(args[0]);
if (num == 1) {
System.out.println("num is " + num);
} else if (num == 2) {
System.out.println("num is" + num);
} else {
System.out.println("num is not 1 and 2");
}
}
just change program argument, we can change result of processing.
問題の実装方法
問題１
上のプログラムのプログラム引数に"3"を渡してelse文の部分を表示させてください。
change upper program and use program argument of 3 show "num is not 1 and 2"
問題２
上のプログラムの「int num = ...」を「String str = 」に変更してプログラムを動くようにしてください。
でわでわ、良い日を。。。
Change A part of "int num = ..." to "String str = ..." and fix the program.
